Upload Image To SQLite3 using PHP

By CampCodes Administrator

Updated on:

upload image to sqlite3

In this tutorial, we will create an Upload Image To SQLite3 using PHP. This code will upload image data to SQLite database when the user clicks the upload button. The system uses PHP POST method to call a specific function that uploads the image data to SQLite database using the INSERT query. This a free program, you can apply this to your system as your own.

We will be using SQLite that provides an interface for accessing the database. It includes class interfaces to the SQL commands. And also it allows you to create SQL functions and aggregate using PHP.

Getting started:

First, you have to download & install XAMPP or any local server that run PHP scripts. Here’s the link for XAMPP server https://www.apachefriends.org/index.html.

And, this is the link for the bootstrap that I used for the layout design https://getbootstrap.com/.

Installing SQLite Browser

We will now then install the SQLite data viewer, here’s the link for the DB Browser for SQLite http://sqlitebrowser.org/.

Setting Up SQLite

First, we are going to enable SQLite 3 in our PHP.

  1. Open localhost server folder XAMPP, etc. and locate php.ini.
  2. Open php.ini and enable sqlite3 by removing the semicolon in the line.

Upload Image to SQLite3

Save changes and Restart Server.

Creating the database connection

Open your any kind of text editor(notepad++, etc..). Then just copy/paste the code below then name it conn.php.

<?php
    $conn=new SQLite3('db/db_image') or die("Unable to open database!");
    $query="CREATE TABLE IF NOT EXISTS `image`(image_id INTEGER PRIMARY KEY AUTOINCREMENT NOT NULL, image_name TEXT, location TEXT)";
 
    $conn->exec($query);
?>

Creating The Interface

This is where we will create a simple form for our application. To create the forms simply copy and write it into you text editor, then save it as index.php.

READ ALSO:   Send POST Request Using Ajax in PHP

<!DOCTYPE html>
<html lang="en">
    <head>
        <meta charset="UTF-8" name="viewport" content="width=device-width, initial-scale=1" />
        <link rel="stylesheet" type="text/css" href="css/bootstrap.css" />
    </head>
<body>
    <nav class="navbar navbar-default">
        <div class="container-fluid">
            <a class="navbar-brand" href="https://sourcecodester.com">Sourcecodester</a>
        </div>
    </nav>
    <div class="col-md-3"></div>
    <div class="col-md-6 well">
        <h3 class="text-primary">PHP - Upload Image To SQLite3</h3>
        <hr style="border-top:1px dotted #ccc;"/>
        <div class="col-md-4">
            <form method="POST" action="upload.php" enctype="multipart/form-data">
                <div class="form-group">
                    <label>Uploade here</label>
                    <input type="file" name="image" required="required" class="form-control"/>
                </div>
                <center><button class="btn btn-primary" name="upload">Upload</button></center>
            </form>
        </div>
        <div class="col-md-8">
            <table class="table table-bordered">
                <thead class="alert-info">
                    <tr>
                        <th>Image</th>
                        <th>Image Name</th>
                        <th>Location</th>
                    </tr>
                </thead>
                <tbody>
                    <?php
                        require'conn.php';
 
                        $query=$conn->query("SELECT * FROM `image`") or die("Failed to fetch row!");
                        while($fetch=$query->fetchArray()){
                            echo"<tr><td><img src='".$fetch['location']."' heigth='70px' width='70px'></td><td>".$fetch['image_name']."</td><td>".$fetch['location']."</td></tr>";
                        }
                    ?>
                </tbody>
            </table>
        </div>
    </div>
</body>	
</html>

Creating the Main Function

This code contains the main function of the application. This code will upload the image data to SQLite database. To do this just copy and write these block of codes as shown below inside the text editor, then save it as upload.php.

<?php
    require_once 'conn.php';
 
    if(ISSET($_POST['upload'])){
        $file_name = $_FILES['image']['name'];
        $file_temp = $_FILES['image']['tmp_name'];
 
        $exp = explode(".", $file_name);
        $ext = end($exp);
        $image = time().'.'.$ext;
        $ext_allowed = array("png", "gif", "jpeg", "jpg");
        $location = "uploads/".$image;
        if(in_array($ext, $ext_allowed)){
            if(move_uploaded_file($file_temp, $location)){
                $query="INSERT INTO `image` (image_name, location) VALUES('$image', '$location')";
 
                $conn->exec($query);
 
                echo "<script>alert('Image uploaded!')</script>";
                echo "<script>window.location='index.php'</script>";
            }
        }else{
            echo "<script>alert('Only image to upload!')</script>";
            echo "<script>window.location='index.php'</script>";
        }
    }
?>
There you have it we successfully created a Upload Image To SQLite3 using PHP. I hope that this simple tutorial help you to what you are looking for. For more updates and tutorials just kindly visit this site. Enjoy Coding!!!

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